Question

x^2+4√2x+5 solve it​

Answer 1

$\Large{\underline{\underline{\mathfrak{\bf{Question}}}}}$

x² + 4√2x + 5 = 0, solve it.

$\Large{\underline{\underline{\mathfrak{\bf{Solution}}}}}$

By Dhracharya Formula

$\boxed{\sf{\red{\:x\:=\:\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}}}$

where,

• a = 1
• b = 4√2
• c = 5

Keep all values,

$\mapsto\sf{\:x\:=\:\dfrac{-4\sqrt{2}\pm\sqrt{(4\sqrt{2})^2-4.1.5}}{2.1}} \\ \\ \\ \mapsto\sf{\:x\:=\:\dfrac{-4\sqrt{2}\pm\sqrt{(4\sqrt{2})\times (4\sqrt{2})-20}}{2}} \\ \\ \\ \mapsto\sf{\:x\:=\:\dfrac{-4\sqrt{2}\pm\sqrt{32-20}}{2}} \\ \\ \\ \mapsto\sf{\:x\:=\:\dfrac{-4\sqrt{2}\pm\sqrt{12}}{2}} \\ \\ \\ \mapsto\sf{\:x\:=\:\dfrac{-4\sqrt{2}\pm 2\sqrt{3}}{2}}$

First, take (+ ve) sign.

$\mapsto\sf{\:x\:=\:\dfrac{-4\sqrt{2}+2\sqrt{3}}{2}} \\ \\ \\ \mapsto\sf{\:x\:=\:\dfrac{2(-2\sqrt{2}+\sqrt{3})}{2}} \\ \\ \\ \mapsto\sf{\orange{\:x\:=\:(-2\sqrt{2}+\sqrt{3})}}$

Second, take ( - ve) sign.

$\mapsto\sf{\:x\:=\:\dfrac{-4\sqrt{2}-2\sqrt{3}}{2}} \\ \\ \\ \mapsto\sf{\:x\:=\:\dfrac{2(-2\sqrt{2}-\sqrt{3})}{2}} \\ \\ \\ \mapsto\sf{\orange{\:x\:=\:(-2\sqrt{2}-\sqrt{3})}}$

$\Large{\underline{\mathfrak{\bf{Hence}}}}$

$\mapsto\sf{\:value\:of\:x\:=\:(-2\sqrt{2}-\sqrt{3})\:\:and\:\:(-2\sqrt{2}+\sqrt{3})}$