Question

x^2-4√2x+6=0 by complete square method​

Answer 1

Step-by-step explanation:

x² - 4√2x + 6 = 0

x² - 4√2x = -6

half of middle term 4√2/2 = 2√2

and add in both side with squaring

x² - 4√2x + (2√2)² = -6 + (2√2)²

(x - 2√2)² = -6 + 8

(x - 2√2)² = 2

x - 2√2 = ±√2

x - 2√2 = √2 , x - 2√2 = -√2

x = √2 + 2√2 , x = -√2 + 2√2

x = 3√2 , x = √2

Answer 2

Step-by-step explanation:

add both side is (b/2a)^2

by this

(4√2/2*1)^2

(2√2)^2