Question

X^2-4√2x+6=0 by factorisation method

Answer 1

GIVEN
X^2-4√2x+6=0

FACTORIZE
${x}^{2} - 3 \sqrt{2} x \: - \sqrt{2}x \: + 6 = 0 \\ x(x - 3 \sqrt{2} ) - \sqrt{2} (x - 3 \sqrt{2} ) = 0 \\ (x - 3 \sqrt{2} ) \: (x - \sqrt{2} ) = 0 \\ x - 3 \sqrt{2} = 0 \: and \: x - \sqrt{2} = 0 \\ x = 3 \sqrt{2} \: and \: x = \sqrt{2} \\ therefore \: the \: factors \: are \: (x - 3 \sqrt{2} )and \: (x - \sqrt{2} ) \: and \: the \: value \: of \: x \: are \: 3 \sqrt{2} \: and \: \sqrt{2}$

Answer 2

Hey user !!

Here is your answer !!

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❗ Given ->

x^2 - 4√2 x + 6 = 0

❗ Solution ->

↪Split the middle term .!

↪x^2 - 3√2 x - 1 √2x + 6 = 0

↪x ( x - 3√2 ) - √2 (x - 3√2 ) = 0

↪(x - √2) ( x - 3√2x ) = 0 ( Factors)

↪x - √2 = 0 , x -3√2 = 0

↪x = +√2 , x = +3√2

↪You can also try this by discriminant method using quadratic formula ..!

Hope it is satisfactory :-)

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