Question

x ²-4 ax + 4a²-b²=0 solve the following by either quadratic equation formula or by factorisation method.​

Answer 1

Answer:

x² -4ax +4a² -b² =0

[ x² -4ax +(2a)² ] - b² =0

Making perfect square, we get

( x-2a )² - b² = 0

Using p² - q² = ( p+q ) × ( p- q ),

( x-2a+b ) × ( x-2a-b ) = 0

x = 2a-b , 2a+b

Step-by-step explanation:

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