Math, asked by Anonymous, 8 months ago

x^2-4/x^2=3 then x=​

Answers

Answered by adithyasathishkumar
1

Answer:

x²-4/x²=3

(x⁴/x²)-4/x²=3

(x⁴-4)/x²=3

x⁴-4=3x²

x⁴-3x²-4=0

x⁴+1x²-4x²-4=0

x²(x²-1)-4(x²-1)=0

(x²-4)(x²-1)=0

x²-4 = 0 , x²-1 = 0

x=√4=2 , x=√1=1

x=2,1

Answered by tennetiraj86
2

Answer:

answer for the given problem is given

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