Question

(x^2 - 4) + (x^2 + 4) + 16

Answer 1

hope that helps......

Answer 2

Answer:

$2 {x}^{2} + 16$

Step-by-step explanation:

${x}^{2} - 4 + {x}^{2} + 4 + 16 \\ = 2 {x}^{2} + 16$

As the terms +4 and -4 cancells out, and the terms

${x}^{2}$

get summed up to

$2 {x}^{2}$