Question

x^2 -4ax +4a^2 -b^2 =0 solve this using factorizatio​

Answer 1

Given :-

• x² - 4ax + 4a² - b² = 0

To Find :-

• Value of x

Formula to be used :-

• ( a - b)² = a² - b² - 2ab

Solution :-

$\sf{x^2-4ax+4a^2-b^2=0}\\\\\sf{\to (x)^2-2 \times 2a \times x+(2a)^2-b^2=0}\\\\\sf{\to (x-2a)^2-b^2=0 }\\\\\sf{\to (x-2a)^2=b^2}\\\\\sf{\to (x-2a)=b}\\\\\sf{\to x=b+2a}</p><p></p><p>$

Hence,

the value of x is = b + 2b

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Some Identities :-

• ( a + b)² = a² + b² + 2ab

• a² - b² = ( a + b) ( a - b)

• ( x + a) ( x + b) = x² + ( a + b) x + ab