Question

x^2 - 4ax - b^2 - 4a^2 = 0
Solve it. I ​

Answer 1

Hey mate

I think your question is wrong

See my answer

x^2-4ax+4a^2-b^2=0

x^2-2*2a*x+(2a)^2-(b)^2=0

(x-2a)^2-(b)^2=0

(x-2a-b)(x-2a+b)=0

x-2a-b=0 x-2a+b=0

x=b+2a x=2a-b

Therefore, x= 2a+b or 2a-b

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