Question

x^2 -4ax -b^2+4a^2 = 0 x2 −4ax−b2 +4a2 =0​

Answer 1

Answer:

x=(2a+b) or (2a-b)

Step-by-step explanation:

x^2-4ax-b^2+4a^2=0

x^2-4ax+4a^2-b^2=0

x^2 - (2a+b)x - (2a-b)x + 4a^2 - b^2 = 0

x (x-2a-b) - (2a-b) (x-2a-b) = 0

(x-2a-b) (x-2a+b) = 0

so,

x = (2a+b) or (2a-b)