Question

x^2+4x+1=0 find zeros
​

Answer 1

$\bf\ using \: quadratic \: equtation \\ \\ \sf\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ \sf\huge \: \: {x}^{2} + 4x + 1 \\ \\ \sf\ x\implies: \frac{ - 4± \sqrt{ {4}^{2} - 4 \times 1 \times 1} }{2 \times 1} \\ \\ \sf\ x \implies: \frac{ - 4 ±\sqrt{16 - 4} }{2} \\ \\ \sf\ x \implies: \frac{ - 4 \sqrt{12} }{2} \\ \\ \sf\ x \implies: \frac{ - 4±2 \sqrt{3} }{2} \\ \\ \sf\ x \implies: - 2± \sqrt{3} \\ \\ \bf\boxed{ \therefore \: x = - 2 + \sqrt{3} \: and \: - 2 - \sqrt{3} }$