Math, asked by nandinijaiswals, 1 year ago

x^2-4x-1=0 the value of X is?


MDirfankhan: hii
niral: x is an element of {(root5+2)} , (root -5 +2)}

Answers

Answered by Anonymous
1

Solution:

The Given Equation is x² - 4x - 1 = 0

Let Polynomial be f(x) = x² - 4x - 1 = 0

Now, Solving Equation!

x² - 4x - 1 = 0

By Quadratic Equation Formula!

Discriminant = b² - 4ac

Discriminant = (-4)² - 4.1.1

Discriminant = 16 - 4

Discriminant , D = 12

Now, Roots of Equation;

☞ -b+√D / 2a 0r -b-√D / 2a

☞ -(-4)+√12/2.1 0r -(-4)-√D/2.1

☞ 4 + √12/2. 0r 4-√12/2

☞ 2 + √3. 0r 2 - √3

Therefore, Roots of Equation are 2 + √3 & 2 - √3.

Answered by Anonymous
0

REFER TO THE ATTACHMENT ❣️

Attachments:
Similar questions