Question

(x^2-4x+3)^1/2+(x^2_9)^1/2=(4x^2_14x+16)^1/2 where x=3 ​

Answer 1

Step-by-step explanation:

(x^2 - 4x + 3)^1/2 + (x^2 - 9)^1/2

substitute x = 3

( 3^2 - 4×3 + 3 )^1/2 + ( 3^2 - 9 )^1/2

( 9 -12 + 3 )^1/2 + ( 9 - 9 )^ 1/2

( 0 )^1/2 + (0)^ 1/2 = 0

(4x^2 - 14x + 16 )^1/2

substituting x = 3

(4 × 3^2 - 14 × 3 + 16)^1/2

( 4×9 - 42 + 16)^1/2

( 36 - 42 + 16)^1/2

(10)^1/2

They are not equal.

. equation went wrong somewhere when stated I think so please check the equation once again

Answer 2

Answer:

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