Question

x^2-4x+3 find zeroes by spitting method​

Answer 1

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Answer 2

Answer:

The zeroes are 1 and 3

Step-by-step explanation:

$x {}^{2} - 4x + 3$

By splitting the middle term , we get,

$x {}^{2} - x - 3x - 3$

$x(x - 1) - 3(x - 1)$

$(x - 3)(x - 1)$

$(x - 1) \: and \: (x - 3) \: are \: equal \: \: to \: when \: x = 1 \: or \: x = 3$

Therefore the zeroes are

$x = 1$

$x = 3$

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