Question

x^2 - 4x + 4y - y^2 factorisation pls solve it​

Answer 1

✤✤✤✤✤✤Question✤✤✤✤✤✤

$\mathtt{factorise} \\ \\ \tt{ {x}^{2} - 4x + 4y - {y}^{2}}$

✤✤✤✤✤✤Solution✤✤✤✤✤✤

$\tt{we \: have} \\ \\ </strong><strong>\tt \: {x}^{2} - 4x + 4y - {y}^{2} \\ \\ \tt{(rearranging \: the \: terms)} \\ \\</strong><strong>\tt {x}^{2} - {y}^{2} - 4x + 4y \\ \\ \tt \: (using\: identity \\ \: \tt( {a}^{2} - {b}^{2} = (a + b)(a - b) ) )\\ \\</strong><strong> \tt \: (x + y)(x - y) - 4x + 4y \\ \\</strong><strong>\tt (x + y)(x - y) - 4(x - y) \\ \\ \tt \: (taking \:(x - y) \: common) \\ \\</strong><strong>\tt (x - y)(x + y - 4)$

$\tt \: hence \: the \: factors \: of \: \\ \tt \: {x}^{2} - 4x + 4y - {y}^{2} are \\</strong><strong> </strong><strong> </strong><strong>{</strong><strong>\boxed</strong><strong> </strong><strong>{ \: (x - y) \: and \: (x + y - 4)}</strong><strong>}</strong><strong>$

Answer 2

Answer:

i hope this may be useful to u