Question

X^2+4x-5=0 Solve the given quadratic equation Pls guys help me !!!!

Answer 1

Answer:

Step-by-step explanation:

x²+4x-5=0

x² -x+5x-5 =0

x(x-1) + 5(x-1) = 0

(x-1)(x+5) = 0

x = 1,-5

Answer 2

Answer:

Step-by-step explanation:

x²+4x-5=0

x²+5x-x-5=0

x(x+5)-1(x+5)=0

(x-1)(x+5)=0

x=1 or -5