Question

X^2— 4x + 5 find zeroes of this.​

Answer 1

Answer:

$x {?}^{2} -4x + 5 = 0 \\ (x - 5)(x + 1) = 0 \\ x - 5 = 0 \: or \: x + 1 = 0 \\ x = 5 \: or \: x = - 1 \\ \\ 5 \: and \: - 1 \: are \: the \: zeroes \: of \: the \: given \: euation$

Answer 2

Answer:

x²-4x+5=0

-b±squareroot of (b²-4ac). /2a

4±square root (16-20)/2

Therefore we get roots are

$4 + 2i \div 2 \: \: 4 - 2i \div 2$

2+i,2-i are roots.