Question

x^2+4x+5 solve by quadratic equations ​

Answer 1

Answer:

x²+4x+5

Step-by-step explanation:

a=1,b=4,c=5

x=-b+-√b²-4ac/2a

x=-4+-√16-20/2

x=-4+-√-4/2

x=-4+-2i/2

x=-2+i, -2-i

Answer 2

x^2+4x-5=0

x^2-1x+5x-5=0

x(x-1)+5(x-1)=0

x+5=0. x-1=0

x=-5. x=1

-5,1 are the zeroes of the quadratic equation x^2+4x-5=0

I hope it's help you

Plz mark my answer as a brainliest answer