|x^2-4x+7|=|2x^2-3x+5| solve for x
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Answer:
x²-4x+7=2x²-3x+5
x²-2x²-4x+3x+7-5=0
-x²-x+2=0
x²+x-2=0
x²+2x-x-2=0
x(x+2)-1(x+2)=0
(x+2)(x-1)=0
x=-2, x=1
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