Question

x^2 +4x+7 split the middle term​

Answer 1

Solution

x²+4x+7

now.....

$b {}^{2} - 4ac = 4 {}^{2} - 4(1)(7) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 16 - 28 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 12 < 0$

so this quadratic equations will not have any real values or zeroes...

so it can't be split into factorised form.

hope this helps you

Answer 2

Step-by-step explanation:

x^2 + 4x + 7

a = 1

b = 4

c = 7

D = b^2 -4ac

= (4)^2 - 4(1) (7)

= 16 - 28

= - 12.

x = -b +√D

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2a

the roots will be no real roots as D = (-12)

hope this helps you...