x^2 +4x+(k+2)=0 if one root is 0 find the value of k
Answers
Answered by
2
Answer:
given,
x^2+4x+k+2=0
one of the root of the above equation is zero
x=0
there fore
0+0+k+2=0
=>k=-2
Answered by
2
AnsWer :
k = - 2.
GiveN :
- x² + 4x + ( k + 2 ) = 0.
- One roots is 0.
To FinD :
The value of K.
SolutioN :
We have, Quadratic Equation.
→ x² + 4x + ( k + 2 ) = 0.
☛ Compare With General Equation.
→ ax² + bx + c = 0.
Where as,
- a = 1.
- b = 4.
- c = k + 2.
Let,
- f( x ) = 0.
So,
→ x² + 4x + ( k + 2 ) = 0.
→ ( 0 ) ² + 4( 0 ) + ( k + 2 ) = 0.
→ k + 2 = 0.
→ k = - 2.
✡ Therefore ,the value of k is - 2.
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