x^2+4y^2=4xy, find the value of x and y?
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Given x^2 + 4y^2 = 4xy can be written as
x^2 + 4y^2 - 4xy = 0
(x - 2y)^2 = 0
x - 2y = 0
x = 2y
x/y = 2/1
The value of x = 2 and the value of y = 1.
Hope this helps!
x^2 + 4y^2 - 4xy = 0
(x - 2y)^2 = 0
x - 2y = 0
x = 2y
x/y = 2/1
The value of x = 2 and the value of y = 1.
Hope this helps!
Answered by
0
x=2. y=1 that is answer
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