x^2 + 4y^2 - z^2 - 4xy
Answers
Answered by
0
Answer:
x^2+4y^2-z^2-4xy
(using a^2+b^2-2ab=(a-b)^2, factorise the expression. )
= (x-2y)^2 - z^2
(now, using a^2-b^2=(a-b)(a+b), factorise the expression)
= (x-2y-z)(x-2y+z
Answered by
0
Answer:
Step-by-step explanation:
Correct option is
A
(z+x−2y)(z−x+2y)
4xy−x
2
−4y
2
+z
2
=z
2
+4xy−x
2
−4y
2
=z
2
−(x
2
−2x(2y)+4y
2
)
=z
2
−(x−2y)
2
=(z+x−2y)(z−x+2y)
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