Question

x^2 =4y then dy/dx atx=2 is .......
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Answer 1

${x}^{2} = 4y$

Differentiate w.r.t X both sides :

$\implies \: \frac{d}{dx} {x}^{2} = \frac{d}{dx} (4y) \\ \\ \implies \: 2 {x}^{2 - 1} = 4 \frac{dy}{dx} \\ \\ \implies \: \frac{dy}{dx} = \frac{2x}{4}$

To find at x=2

$\implies \: \frac{dy}{dx} = \frac{2x}{4} = \frac{4}{4} = 1$

Answer 2

Step-by-step explanation:

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