(x^-2-5) to (x^12-x^3+6)
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(x^-2-5) to (x¹²- x^3+6)
first:-
x^-2 -5
= x^-7
and
x¹² -x^3+6
= x¹²- x^9
= x^12-9
= x³
so when we devide those equations
x³ ÷ x^-7
= x^3-(-7))
= x^3+7
= x^10
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