Question

x/2+5(x/2_x/3)=3(x_x/6) ​

Answer 1

Answer:

(x+2)(x+3)+(x−3)(x−2)−2x(x+1)=0

⇒x

2

+2x+3x+6+x

2

−3x−2x+6−2x

2

−2x=0

⇒2x

2

−2x

2

+5x−5x−2x+12=0

⇒−2x+12=0

⇒−2x=−12

⇒x=6