Question

x-2/5-x-3/6=3/10, then find the value of x.​

Answer 1

From the given question the correct answer is:

the value of x is 2.14

Given :

$\frac{x-2}{5-x} - \frac{3}{6} = \frac{3}{10}$

To find:

value of x

Solution:

Given expression,

$\frac{x-2}{5-x} - \frac{3}{6} = \frac{3}{10}$

$\frac{6(x-2)-3(5-x)}{6(5-x)}$=$\frac{3}{10}$

$\frac{6x-12-15-3x}{30-6x}$$=\frac{3}{10}$

$\frac{3x-3}{30-6x}$$=\frac{3}{10}$

$\frac{x-3}{10-6x}$$=\frac{3}{10}$

we will do cross multiplication.

10(x-3)=3(10-6x)

10x-30=30-18x

now will seprate all same variable at one side

so, 10x+18x=30+30

      28x=60

         x=60/28

         x=2.14

Hence,the value of x 2.14

Answer 2

Given that:-

$\frac{x-2}{5-x} -\frac{3}{6} =\frac{3}{10}$

To find the unknown value of 'x',

By using cross multiplication on LHS we get,

$=>\frac{6(x-2)-3(5-x)}{6(5-x)} =\frac{3}{10}$

$=>\frac{6x-12-15-3x}{30-6x} =\frac{3}{10}$

Now, simplifying it we get,

$=>\frac{3x-3}{30-6x} =\frac{3}{10}$

Divide it by 3 we get,

$=>\frac{x-3}{10-6x}=\frac{3}{10}$

Again by using cross multiplication,

$=>\frac{10(x-3)}{3(10-6x)}$

$=>\frac{10x-30}{30-18x}$

Now, by seprating all the similar variables on one side,

$=>10x+18x=30+30$

$=>28x=60$

$=>x=\frac{60}{28}$

$=>x=2.14$

Hence, the value of x is 2.14