Question

x^2-5kx+ 6k^2=0 is equal to 13 find the value of k. ​

Answer 1

Answer:

Since the above equation has equal roots

Hence

B

2

−4AC=0

Hence

4(2k−3)

2

−4(5k−6)(k−2)=0

4k

2

−12k+9−(5k

2

−16k+12)=0

−k

2

+4k−3=0

Or

k

2

−4k+3=0

(k−3)(k−1)=0

Hence

k=3 and k=1.