Math, asked by san1883, 10 months ago

x^ 2+5x+10=0. answer this question and get 10 points

Answers

Answered by mysticd
0

Answer:

 \red { Values \:of \: x } \green {= \frac{-5±\sqrt{5}}{2}}

Step-by-step explanation:

 Given \: x^{2}+5x+10 = 0

\implies x^{2} + 5x = -10

\implies x^{2} + 2\times x \times \frac{5}{2} = -10

\implies x^{2} + 2\times x \times \frac{5}{2} + \left(\frac{5}{2}\right)^{2}= -10 + \left(\frac{5}{2}\right)^{2}

\implies \left( x + \frac{5}{2}\right)^{2} = -10 + \frac{25}{4}

\implies \left( x + \frac{5}{2}\right)^{2} =\\frac{-20+25}{4}

 = \frac{5}{4}

 \implies \left( x + \frac{5}{2}\right)= ±\sqrt{\frac{5}{4}}\\= ±\frac{\sqrt{5}}{2}

\implies x = \frac{-5}{2} ±\frac{\sqrt{5}}{2}

 = \frac{-5±\sqrt{5}}{2}

Therefore.,

 \red { Values \:of \: x } \green {= \frac{-5±\sqrt{5}}{2}}

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