x^2-5x+13 find the zeros
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Answered by
1
Answer:
x²-5x+13=0
x(x-5)+13=0
x=5
x=-13 OK friend this is urs answer
Answered by
1
Step-by-step explanation:
Given :-.
- x^2-5x+13 find the zeros
To Find :-
- Find the zeros
Quadratic equation:-
Quadratic equation is any equation that can be rearranged in standard form as where x represents an unknown, and a, b, and c represent known numbers, where a ≠ 0. If a = 0, then the equation is linear, not quadratic, as there is no term.
An equation where the highest exponent of the variable (usually "x") is a square (2).
So it will have something like x2.
- But not x3 etc.
- A Quadratic Equation is usually written ax2+ bx + c = 0
Example: 2x^2 + 5x − 3 = 0
Solution :-
A = 1, B = -5, C = 13
=> x = - b ± √b^2- 4ac /2a
=> x = -( - 5 ) ± √ -5^2 - 4 × 1 × 13 / 2 × 1
=> x = 5 ± √ 25 - 52/2
=> x = 5 ± √ -27/2
=> x = 5 + √ -27/2 and x = 5 - √ -27/2 is right answer.
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