Math, asked by sharmilayadav1986, 10 months ago

x^2-5x+13 find the zeros​

Answers

Answered by aryan1234243
1

Answer:

x²-5x+13=0

x(x-5)+13=0

x=5

x=-13 OK friend this is urs answer

Answered by Anonymous
1

Step-by-step explanation:

Given :-.

  • x^2-5x+13 find the zeros

To Find :-

  • Find the zeros

Quadratic equation:-

Quadratic equation is any equation that can be rearranged in standard form as where x represents an unknown, and a, b, and c represent known numbers, where a ≠ 0. If a = 0, then the equation is linear, not quadratic, as there is no term.

An equation where the highest exponent of the variable (usually "x") is a square (2).

So it will have something like x2.

  • But not x3 etc.

  • A Quadratic Equation is usually written ax2+ bx + c = 0

Example: 2x^2 + 5x − 3 = 0

Solution :-

A = 1, B = -5, C = 13

=> x = - b ± b^2- 4ac /2a

=> x = -( - 5 ) ± √ -5^2 - 4 × 1 × 13 / 2 × 1

=> x = 5 ± √ 25 - 52/2

=> x = 5 ± √ -27/2

=> x = 5 + √ -27/2 and x = 5 - √ -27/2 is right answer.

Similar questions