Math, asked by google7987, 3 months ago

(x^2-5x)^2- 36

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Answers

Answered by thusharab
2

Answer:

x^4-10x^3+25x^2-36

Step-by-step explanation:

(x^2-5x)^2-36=(x^2-5x)*(x^2-5x)= x^2*(x^2-5x)-5x*(x^2-5x)

=x^4-5x^3-5x^3+25x^2

=x^4-10x^3+25x^2

(x^2-5x)^2-36=

x^4-10x^3+25x^2-36

Answered by mandalshubhamkumar85
1

Answer:

Find the mean of first ten prime numbers.

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