x^2 – 5x + 2√ (x^2 - 5x + 3) =12
Answers
Answer:
How do I factorise x^2-2√5x+3?
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Vishal Chandratreya
Answered 2 years ago
You do it the usual way.
The coefficient of the middle term is negative, but the constant term is positive. Hence, you must look for two numbers whose sum is 25–√ and product is 3 .
The product being rational, there must be some irrational conjugate multiplication happening here. If two irrational conjugates add to 25–√ , they must be 5–√±c , where c is a number we have to determine.
Their product is 3 . Therefore, (5–√)2−c2=3 . Hence, the two numbers required are 5–√±2–√ .
Express the middle term and the constant in terms of these numbers.
x2−25–√x+3=
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Shambhu Bhat
Answered 2 years ago
x2–25–√x+3
=(x−5–√)2–2
=(x−5–√)2–(2–√)2
=(x−5–√+2–√)(x−5–√−2–√)
Sayan Das
Answered 2 years ago
Mohd Alam
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State Bank of India (SBI)
Answered 1 year ago
Any Individual who desires to open savings bank account in individual capacity need to furnish following documents:- 1. Permanent Account Number (PAN) or Form No. 60 (except in case of small accounts); 2. Photograph; and 3. At least one copy of the any Officially Valid Documents (OVD’s) ment
Lavina Vijay
Answered 2 years ago
The general solution for a quadratic equation of the type
ax^2+bx+c=
(—b+sqrt(b^2– 4ac))/2a and (— b- sqrt(b^2-4ac))/2a
Where a , b , c are constants and a=1.
Here for x^2 — 2×sqrt(5)+3=
(2×sqrt(5)+sqrt(8))/2 , (2×sqrt(5)— sqrt(8))/2
Step-by-step explanation:
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