Math, asked by amandwivedi513, 9 hours ago

x^​2+5x-36=0 can somebody solve this?

Answers

Answered by MrImpeccable
27

ANSWER:

To Solve:

  • x² + 5x - 36 = 0

Solution:

We are given that,

\implies x^2+5x-36=0

On splitting the middle term,

\implies x^2+5x-36=0

\implies x^2+9x-4x-36=0

Taking x common in the first 2 terms,

\implies x(x+9)-4x-36=0

Taking 4 common in the last 2 terms,

\implies x(x+9)-4(x+9)=0

Now, we can see that (x + 9) is common,

\implies x(x+9)-4(x+9)=0

\implies (x+9)(x-4)=0

So,

\implies x+9=0,\:\:x-4=0

Hence,

\implies x=-9,\:\:x=4

Therefore,

\implies\bf x=-9,\:4

Verification:

We had,

\implies x^2+5x-36=0

Case 1: For x = -9

\implies (-9)^2+5(-9)-36=0

\implies 81-45-36=0

\implies 81-81=0

\implies 0=0

As, LHS=RHS

HENCE VERIFIED!!

Case 2: For x = 4

\implies (4)^2+5(4)-36=0

\implies 16+20-36=0

\implies 36-36=0

\implies 0=0

As, LHS=RHS

HENCE VERIFIED!!

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