Question

x^​2+5x-36=0 can somebody solve this?

Answer 1

ANSWER:

To Solve:

• x² + 5x - 36 = 0

Solution:

We are given that,

$\implies x^2+5x-36=0$

On splitting the middle term,

$\implies x^2+5x-36=0$

$\implies x^2+9x-4x-36=0$

Taking x common in the first 2 terms,

$\implies x(x+9)-4x-36=0$

Taking 4 common in the last 2 terms,

$\implies x(x+9)-4(x+9)=0$

Now, we can see that (x + 9) is common,

$\implies x(x+9)-4(x+9)=0$

$\implies (x+9)(x-4)=0$

So,

$\implies x+9=0,\:\:x-4=0$

Hence,

$\implies x=-9,\:\:x=4$

Therefore,

$\implies\bf x=-9,\:4$

Verification:

We had,

$\implies x^2+5x-36=0$

Case 1: For x = -9

$\implies (-9)^2+5(-9)-36=0$

$\implies 81-45-36=0$

$\implies 81-81=0$

$\implies 0=0$

As, LHS=RHS

HENCE VERIFIED!!

Case 2: For x = 4

$\implies (4)^2+5(4)-36=0$

$\implies 16+20-36=0$

$\implies 36-36=0$

$\implies 0=0$

As, LHS=RHS

HENCE VERIFIED!!