x^2-5x+5=0 solve the equation by completing the square?
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∆=b^2 -4ac
=(-5)^2 -4(5)
=25-20
=5
A= -b+rootD/2a
=5+root5/2
B =-b-rootD/2a
=5-root5/2
=(-5)^2 -4(5)
=25-20
=5
A= -b+rootD/2a
=5+root5/2
B =-b-rootD/2a
=5-root5/2
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