Question

x^2+5x+6=0 find value of x?​

Answer 1

Step-by-step explanation:

x²+5x+6=0

x²+3x+2x+6=0

x(x+3)+2(x+3)=0

(x+3)(x+2)=0

THERE ARE TWO FACTOR

(1) (x+3)=0

x= -3

(2) (x+2)=0

x= -2

So the value of x in this question is

(-2,-3)

Answer 2

Answer:

Here goes the solution!

x2 + 5x + 6 = 0

x2 + 3x + 2x + 6 = 0

x(x + 3) + 2(x + 3) = 0

(x + 3) (x + 2) = 0

x = -3, -2