Question

]x^{2} +5x+6=0[/tex]

Answer 1

Answer:

${x}^{2} + 5x + 6 = 0 \\ \\ {x }^{2} + 3x + 2x + 6 = 0 \\ \\ x(x + 3) + 2(x + 3) = 0 \\ \\ (x + 2)(x + 3) = 0 \\ \\ x + 2 = 0 \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \: x + 3 = 0 \\ \\ x = - 2 \: \: \: \: \: \: \: \: \: or \: \: \: \: \: \: \: \: \: \: \: x = - 3 \\ \\ so \: \: \: the \: \: \: roots \: \: \: are \: \: \: - 2 \: \: \: \: \: and \: \: \: \: \: - 3$

Answer 2

$\huge\pink{\boxed{\green{\mathfrak{\fcolorbox{red}{aqua}{\underline{\pink{Answer}}}}}}}$

${ x }^{2} + 5x + 6 = 0 \\ {x}^{2} + (3 + 2)x + 6 = 0 \\ {x}^{2} + 3x + 2x + 6 = 0 \\ x(x + 3) + 2(x + 3) = 0 \\ \implies(x + 2)(x + 3) \\ \\ \\ (x + 2) = 0 \\ x = - 2 \\ \\ (x + 3) = 0 \\ x = - 3$

hope it helps.