Question

x^2-5x+6 find the zero

Answer 1

Expressing x²-5x+6 in multiplication will directly lead you to zero.

→ x²-5x+6

→ The expression is (x-3)(x-2) by the A.C Method.

(x-3)(x-2)=0

x=3 or x=2 solves the equation. Therefore the zeros are 3 and 2.

Answer 2

Answer -

x²- 5x +6 = 0

by middle term splitting

x² -2x-3x +6

x(x-2)-3(x-2)

(x-3)(x-2) = 0

for product to be zero one of them should become zero.

x-3= 0

x= 3

x-2 = 0

x= 2

therefore,

${\pink{\boxed{x = 2,3}}}$

2 and 3 are zeroes of x²-5x+6.

Extra information-

$\underline{\sf{Types\ of\ algebric\ expressions:}} \\ \\ \tt On\ the\ basis\ of\ degree \begin{cases} \rightarrow Linear\\ \rightarrow Quadratic \\ \rightarrow Cubic \\ \rightarrow Biquadratic\end{cases} \\ \\ \\ and \\ \\ \\ \bf On\ the\ basis\ of\ variables \begin{cases} \rightarrow One\ Variable\\ \rightarrow Two\ Variable\end{cases}$