Math, asked by sagarsagar2559, 8 months ago

x^2-5x-6 solve by factorisation methode​

Answers

Answered by kanchankumari0201198
1

Answer:

question galat hai +6 hoga

x^2-3x-2x+6

x(x-3) -2(x-3)

(x-2) (x-3)

Ram ram mithe

Answered by bhuvanah2012
1

Answer:

(x+2)(x-3)

Step-by-step explanation:

x^2-5x-6\\

this equation can be factorised by splitting middle term ,

so, first take the factors of last term 6,

the factors are :

  • 2*3  
  • 6*1

now check the factors.

the factors should be added or subracted ,so we can get the middle term....

now , i have taken 2*3 to split my middle term,

x^2-3x+2x-6\\

take the common factors out from the first and last 2 terms

x(x-3)+2(x-3)\\(x+2)(x-3)

the answer is  (x+2)(x-3)

hope answer is useful.....

plz mark as brainliest

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