Math, asked by devrakhecha123456, 10 months ago

x^2+5x-(a^2+a-6)=0
solve for x​

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Answered by prashantyadav9336
2

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Answered by Anonymous
2

hlo mate Zara brainliest karna

Hello friend !!

x2+5x−(a2+a−6)=0

⇒x2+5x−(a2+3a−2a−6)=0

⇒x2+5x−(a(a+3)−2(a+3))=0

⇒x2+5x−(a+3)(a−2)=0

⇒x2+[(a+3)−(a−2)]x−(a+3)(a−2)=0

⇒x2+(a+3)x−(a−2)x−(a+3)(a−2)=0

⇒x[x+(a+3)]−(a−2)[x+(a+3)]=0

⇒[x+(a+3)][x−(a−2)]=0

⇒[x+(a+3)]=0 or [x−(a−2)]=0

⇒x=−(a+3) or x=(a−2)

Hope it helps. abb der mt krr

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