x^2 – 5x + c = 0
In the quadratic equation above, c is a constant.
If the equation has two solutions for x, one of
which is -3, what is the value of the other
solution?
Answers
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2
Answer:
8
Step-by-step explanation:
substitute -3 in the given quadratic equation:
(-3)² - 5(-3) + c = 0
Solving for c:
c = -24
the quadratic equation will be:
x² - 5x - 24 = 0
solving for the value of x using quadratic formula:
x = [-b ±√(b² - 4(a)(c) )]/2a
x = [-(-5) ± √((-5)² - 4(1)(-24))]/2(1)
x = 8, -3
therefore the other solution is 8
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