x^2-5x+k=0, if x+1 is a factor , then k is
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Answered by
1
Answer:
f(x)=x^2-5x+k=0
g(x)=x+1=0
=x=-1
f-1)=(-1)^2-5×(-1)+k=0
=1+5+k=0
=6+k=0
=k=-6
Answered by
0
Answer:
k = -6
Step-by-step explanation:
If x + 1 is the factor then,
x = -1 is the zero of the p(x).
Here,
∴ x² - 5x + k = 0
∴ (-1)² - 5(-1) + k = 0 [substitute x = -1]
∴ 1 + 5 + k = 0
∴ 6 + k = 0
∴ k = -6
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