Question

(x+2)÷6-[(11-x÷3)-(1÷4)]=(3x-14)÷12

Answer 1

do by BODMAS first solve the bracket of division then multiplication then addition and finally of subtraction and then simplify u will surely get the correct answer

Answer 2

Step-by-step explanation:

$\mathsf{Given : \dfrac{x + 2}{6} - \bigg(\dfrac{11 - x}{3} - \dfrac{1}{4}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{4(11 - x) - 3}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{44 - 4x - 3}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{41 - 4x}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \bigg(\dfrac{x + 2}{6} - \dfrac{(41 - 4x)}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{2(x + 2) - (41 - 4x)}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{2x + 4 - 41 + 4x}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{-37 + 6x}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies {-37 + 6x} = {3x - 4}}$

$\mathsf{\implies 6x - 3x = 37 - 4}$

$\mathsf{\implies 3x = 33}$

$\mathsf{\implies x = \dfrac{33}{3}}$

$\mathsf{\implies x = 11}$