Question

x+2/6 - (11-x/3 - 1/4) = 3x-4/12

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Answer 1

Answer:

\frac{x+2}{6} - ( \frac{44-4x-3}{12}) = \frac{3x-4}{12}

6

x+2

−(

12

44−4x−3

)=

12

3x−4

\frac{x+2}{6} - ( \frac{41-4x}{12}) = \frac{3x-4}{12}

6

x+2

−(

12

41−4x

)=

12

3x−4

\frac{2x+4-41+4x}{12} = \frac{3x-4}{12}

12

2x+4−41+4x

=

12

3x−4

\frac{6x-37}{12} = \frac{3x-4}{12}

12

6x−37

=

12

3x−4

6x-37 = 3x - 46x−37=3x−4

3x=333x=33

x= \frac{33}{3}x=

3

33

x=11x=11

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\mathsf{Given : \dfrac{x + 2}{6} - \bigg(\dfrac{11 - x}{3} - \dfrac{1}{4}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{4(11 - x) - 3}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{44 - 4x - 3}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{x + 2}{6} - \bigg(\dfrac{41 - 4x}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \bigg(\dfrac{x + 2}{6} - \dfrac{(41 - 4x)}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{2(x + 2) - (41 - 4x)}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{2x + 4 - 41 + 4x}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies \dfrac{-37 + 6x}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\implies {-37 + 6x} = {3x - 4}}$

$\mathsf{\implies 6x - 3x = 37 - 4}$

$\mathsf{\implies 3x = 33}$

$\mathsf{\implies x = \dfrac{33}{3}}$

$\mathsf{\implies x = 11}$

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