Question

(x^2-6)+(x^2+6)+36..............

Answer 1

$\mathcal{\huge{\purple{\star\:Hayy \: Mate...!! \:\star}}}$

$(x ^{2} - 6) + ( {x}^{2} + 6) + 36$

${x }^{2} - 6 + {x}^{2} + 6 + 36$

$2 {x}^{2} ( - 6 + 6) + 36$

$- 6 + 6 \: \: are \: canseled$

$2 {x}^{2} + 36$

$2 {x}^{2} + 36 = 0$

$2 {x}^{2} = - 36$

$2x = - 6$

$x = - 6 \div 2$

$x = - 3$

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