Question

x^-2=64 find the value of x1/3+x^0​

Answer 1

Answer:

${x}^{ - 2} = 64$

$\frac{1}{ {x}^{2} } = 64$

taking square root.

$\frac{1}{x} = 8$

$x = \frac{1}{8}$

$\frac{1}{3} + 1$

$\frac{4}{3}$

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Step-by-step explanation:

${x}^{ \frac{1}{3} } + {x}^{0}$

${ \frac{1}{8} }^{ \frac{1 }{3} } + 1$