Question

(x-2)/(6x+1)=1 i need it with steps

Answer 1

Hey mate here is your solution....

Answer 2

Heya !!!

Here is your answer,

$\frac{(x - 2)}{(6x + 1)} = 1 \\ \\ (we \: \: can \: \: take \: 1 \: as \: \frac{1}{1} \: \: ) \\ \\ \frac{(x - 2)}{(6x + 1)} = \frac{1}{1} \: \: \: \: \: \: (cross \: \: multilication) \\ \\ = > 1 \times (x - 2) = 1 \times (6x + 1) \\ \\ = > x - 2 = 6x + 1 \\ \\ = > - 2 - 1 = 6x - x \\ \\ = > - 3 = 5x \\ \\ = > \frac{ - 3}{5} = x$


Verification


$\frac{(x - 2)}{(6x + 1)} \: \: \: \: \: L.H.S \\ \\ put \: \: the \: \: value \: \: of \: \: x \: = \frac{ - 3}{5} \\ \\ \\ = \frac{ (\frac{ - 3}{5}) - 2}{(6 \times \frac{ - 3}{5}) + 1} = \frac{ (\frac{ - 3}{5}) - 2 }{( \frac{ - 18}{5}) + 1 } \\ \\ take \: L.C.M = 5 \\ \\ = \frac{ (\frac{ - 3 - 10}{5}) }{( \frac{ - 18 + 5}{5} )} = \frac{ (\frac{ - 13}{5} )}{( \frac{ - 13}{5} )} \\ \\ \\ = ( \frac{ - 13}{5} ) \div ( \frac{ - 13}{5}) = 1 \: \: \: \: ( = R.H.S)$


Hence, L.H.S = R.H.S



Hole it helps.