Question

x^2+6x-10=0 using quadratic equation

Answer 1

Answer

First we have to compare it with ax^2+bx-c=0

And then find Delta

Then we get answer

Answer 2

Answer:

$x= \frac{-6+\sqrt{76}}{2}$ , $x= \frac{-6-\sqrt{76}}{2}$

Step-by-step explanation:

We need to solve the provided quadratic equation $x^{2} + 6x -10 =0$

Roots of  quadratic equation $a^{2} + bx + c =0$ is calculated by :

$x= \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

First, compare $x^{2} + 6x -10 =0$ with $a^{2} + bx + c =0$

Here a = 1 , b = 6 and c = -10

Now, solve for x using $x= \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}$

$x= \frac{-6\pm \sqrt{6^{2}-4(1)(-10)}}{2(1)}$

$x= \frac{-6\pm \sqrt{36+40}}{2}$

$x= \frac{-6\pm \sqrt{76}}{2}$

Hence $x= \frac{-6 + \sqrt{76}}{2}$ , $x= \frac{-6-\sqrt{76}}{2}$