Question

x^2-6x+10 is to be written in the form (x+p)^2+q. Find the values of p and q

Answer 1

Answer: p= -3, q= 1

Step-by-step explanation:

Ad per question,

x^2-6x+10 = (x+p)^2+q

Now, solving, x^2-6x+10, by completing the Square Method.......

x^2-6x+10 = x^2-6x + 9- 9+10

= [x^2-6x + 9] -9+10

= [x^2-6x + 3^2] +1

= (x-3) ^2 +1

So, x^2-6x+10 = (x-3) ^2 +1= (x+p)^2+q

(x-3) ^2 +1= (x+p)^2+q

On comparing, we get,

p= -3, q= 1