Question

X ^2 -6x+3=0 solve by the method of completing the square

Answer 1

Answer:

Refer the attachment hope this helps u

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Answer 2

Answer:

$\alpha = 3 + \sqrt{6} \\ \beta = 3 - \sqrt{6}$

step by step explaination

${x}^{2} - 6x + 3$

${x}^{2} - 6x = - 3$

${x}^{2} - 6x + {3}^{2} = - 3 + {3}^{2}$

$({x - 3)}^{2} = - 3 + 9$

$( {x - 3)}^{2} = 6$

$x - 3 = + - \sqrt{6}$

$x = 3 + - \sqrt{6}$

•°•

$\alpha = 3 + \sqrt{6}$

$\beta = 3 - \sqrt{6}$

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