Question

X^2+6x+4 slove it by splitting middle term. How i do it

Answer 1

${x}^{2} + 6x + 4 = 0 \\ {x}^{2} + (3 + \sqrt{5} )x + (3 - \sqrt{5} )x + (3 + \sqrt{5} )(3 - \sqrt{5} ) = 0 \\ x(x + 3 + \sqrt{5} ) + (3 - \sqrt{5} )( x + 3 + \sqrt{5} ) = 0 \\ (x + 3 + \sqrt{5} )(x + 3 - \sqrt{5} ) = 0 \\ = > x = - 3 + \sqrt{5} \\ = > x = - 3 - \sqrt{5}$
hope it helps

Answer 2

this is the completing square method



hope you will satisfy with this ans........