x^2+6x-567ko purna varg bnakan gudankhand
Answers
Step-by-step explanation:
Step by step solution :
STEP1:Trying to factor by splitting the middle term
1.1 Factoring x2+6x-567
The first term is, x2 its coefficient is 1 .
The middle term is, +6x its coefficient is 6 .
The last term, "the constant", is -567
Step-1 : Multiply the coefficient of the first term by the constant 1 • -567 = -567
Step-2 : Find two factors of -567 whose sum equals the coefficient of the middle term, which is 6 .
-567 + 1 = -566 -189 + 3 = -186 -81 + 7 = -74 -63 + 9 = -54 -27 + 21 = -6 -21 + 27 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -21 and 27
x2 - 21x + 27x - 567
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (x-21)
Add up the last 2 terms, pulling out common factors :
27 • (x-21)
Step-5 : Add up the four terms of step 4 :
(x+27) • (x-21)
Which is the desired factorization
Equation at the end of step1:
(x + 27) • (x - 21) = 0
STEP2:Theory - Roots of a product
2.1 A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as